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CODING SOLUTION - Placement Jobs & Materials

Logo of telegram channel codingsolution_it — CODING SOLUTION - Placement Jobs & Materials C
Logo of telegram channel codingsolution_it — CODING SOLUTION - Placement Jobs & Materials
Channel address: @codingsolution_it
Categories: Technologies
Language: English
Subscribers: 202.72K
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🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “
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The latest Messages 66

2022-04-24 12:45:51
Java8
Gcd code
Telegram - t.me/codingsolution_IT
15.7K views09:45
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2022-04-24 12:45:07
Python
Factor dilemma Code
Telegram - t.me/codingsolution_IT
15.0K views09:45
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2022-04-24 12:39:47
Java
Divine to sequence
Telegram - t.me/codingsolution_IT
15.2K viewsedited  09:39
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2022-04-24 10:43:01
Python
LIS Problem Code
Telegram - t.me/codingsolution_IT
17.5K views07:43
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2022-04-24 09:51:19 def isPalindrome(Str):


Len = len(Str)



if (Len == 1):

return True




ptr1 = 0




ptr2 = Len - 1


while (ptr2 > ptr1):


if (Str[ptr1] != Str[ptr2]):

return False

ptr1 += 1

ptr2 -= 1


return True



def noOfAppends(s):


if (isPalindrome(s)):

return 0




del s[0]


return 1 + noOfAppends(s)

//CodingSolution

se = "abede"

s = [i for i in se]
print(noOfAppends(s))

Python
Make palindrome code
Telegram - t.me/codingsolution_IT
20.2K viewsedited  06:51
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2022-04-24 09:22:29
Python
A lot of sum Code
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19.5K views06:22
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2022-04-24 09:16:36
Python
Positive sum segment code
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19.1K views06:16
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2022-04-24 09:13:24
Python
Maximise multiplication code
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18.2K views06:13
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2022-04-24 09:08:27
Python
TCS CPA Code
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18.2K views06:08
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2022-04-24 08:56:02 #include
using namespace std;

// Function to check whether given sequence is
// Jolly Jumper or not
bool isJolly(int a[], int n)
{
// Boolean vector to diffSet set of differences.
// The vector is initialized as false.
vector diffSet(n, false);

// Traverse all array elements
for (int i=0; i < n-1 ; i++)
{
// Find absolute difference between current two
int d = abs(a[i]-a[i+1]);

// If difference is out of range or repeated,
// return false.
if (d == 0 d > n-1 diffSet[d] == true)
return false;

// Set presence of d in set.
diffSet[d] = true;
}

return true;
}

// Driver Code
int main()
{
int a[] = {11, 7, 4, 2, 1, 6};
int n = sizeof(a)/ sizeof(a[0]);
isJolly(a, n)? cout << "Yes" : cout << "No";
return 0;
}

C++
Jolly Jumper Sequence Code
Telegram - t.me/codingsolution_IT
18.6K viewsedited  05:56
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