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x̅= (x₁+x₂+ x₃+....xₙ)/n ∑(x₁- x̅)==(x₁+x₂+ x₃+....xₙ)- nx̅ | Algebra Quint

x̅= (x₁+x₂+ x₃+....xₙ)/n

∑(x₁- x̅)==(x₁+x₂+ x₃+....xₙ)- nx̅

∑(x₁- x̅)== nx̅-nx̅==0