Aptitude Quiz by AptiRanker

2020-12-27 11:45:54 #Solution of above quant has been explained. So if you wish to first solve the question, then stop reading and solve the question first,
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Amount = 3 P; Time = 10 years

Simple interest
= (P x R x T)/100

Let principal is P, Amount = 3P
=> S.I. = 2P

S.I. = (P x R x T)/100

2P = (P x R x 10/100

R= 20%
=> Rate is 20 % per annum. Open / Comment

2020-12-27 11:45:44 #Solution of above quant has been explained. So if you wish to first solve the question, then stop reading and solve the question first,
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Cost price of calculator for Arun = Rs. 271.4

Let the C.P. of calculator for Karan is Rs. X

X×(118/100) × (115/100) = 271.4

X= (271.4 x 100 x 100/118 × 115)

=> X = 23000/115
=> X = Rs. 200 Open / Comment

2020-12-20 06:45:24 #Solution of above quant has been explained. So if you wish to first solve the question, then stop reading and solve the question first,
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Let the two numbers be x and y
respectively
Now, According to question
x - y = 85 --(i)
52% of a number is qual to 69% of another number
52x/100 = 697/100


52x = 69y
=>x = 69y/52...(ii)

Putting (ii) in (i)
(69y/52) - y = 85

17y/52 = 85
y = 260
x - 260 = 85
=> x = 345 Open / Comment