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Code With Virus

Logo of telegram channel codewithvirus — Code With Virus C
Logo of telegram channel codewithvirus — Code With Virus
Channel address: @codewithvirus
Categories: Technologies
Language: English
Subscribers: 14.46K
Description from channel

Coding channel @codewithvirus. 👈
Main group @avirustech 👈
Accenture @Accenturavirustech 👈
IBM. @IBMavirustech 👈
Tech Mahindra. @TechMavirustech 👈

Ratings & Reviews

2.50

2 reviews

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The latest Messages 2

2023-07-23 14:06:45
https://t.me/AccenturExam
Python
@AccenturExam
@AccenturExam
@AccenturExam
@AccenturExam

https://bit.ly/codewithanusha
627 viewsedited  11:06
Open / Comment
2023-07-23 14:05:07
https://t.me/AccenturExam
Python
@AccenturExam
@AccenturExam
@AccenturExam
@AccenturExam

https://bit.ly/codewithanusha
597 viewsedited  11:05
Open / Comment
2023-07-23 13:23:52
https://t.me/AccenturExam
Python
@AccenturExam
@AccenturExam
@AccenturExam
@AccenturExam

https://bit.ly/codewithanusha
526 viewsedited  10:23
Open / Comment
2023-07-04 20:38:55 Company: HCL
Role: Software Engineer
Batch: 2023
Apply Link: https://www.linkedin.com/jobs/view/3625524294

Click here to apply
https://bit.ly/codewithanusha
572 views17:38
Open / Comment
2023-07-04 20:35:59 Company: Hewlett Packard
Role: R&D Graduate
Batch: 2023, 2022
Apply Link: https://careers.hpe.com/us/en/job/HPE1US1115587EXTERNALENUS/R-D-Graduate

Click here to apply
https://bit.ly/codewithanusha
573 viewsedited  17:35
Open / Comment
2023-07-04 20:32:45 Company: Zoho
Role: Technical Support Engineer
Batch: 2023
Apply Link: https://www.zoho.com/careers/jobdetails/?job_id=2803000614929125

Click here to apply
https://bit.ly/codewithanusha
532 viewsedited  17:32
Open / Comment
2023-07-03 14:05:34
Pouring Problem
python
https://bit.ly/codewithanusha
744 viewsedited  11:05
Open / Comment
2023-07-03 13:58:15
int AddDistinctSubDuplicate(int a, int b, int c, int d) {
int sum = 0;
int dsum = 0;
if (a != b && a != c && a != d) {
sum += a;
}
if (b != a && b != c && b != d) {
sum += b;
}
if (c != a && c != b && c != d) {
sum += c;
}
if (d != a && d != b && d != c) {
sum += d;
}
if (a == b && a != c && a != d) {
dsum = a;
}
if (a == c && a != b && a != d) {
dsum = a;
}
if (a == d && a != b && a != c) {
dsum = a;
}
if (b == c && b != a && b != d) {
dsum = b;
}
if (b == d && b != a && b != c) {
dsum = b;
}
if (c == d && c != a && c != b) {
dsum = c;
}

int result = sum - dsum ;
return result;
}

c++

https://bit.ly/codewithanusha
638 views10:58
Open / Comment
2023-07-03 13:39:16
python


https://bit.ly/codewithanusha
495 viewsedited  10:39
Open / Comment
2023-07-03 13:28:41
python

Distinct and Duplicate Integers

https://bit.ly/codewithanusha
608 viewsedited  10:28
Open / Comment