def matrix(arr, m, ans): for i in range(m): for j | CODING SOLUTION - Placement Jobs & Materials

def matrix(arr, m, ans):
for i in range(m):
for j in range(len(arr[i])):
ele = arr[i][j]
key = ele
dic.setdefault(key, [])
dic[key].append([i, j])
for k, v in dic.items():
count = 1
v.sort()
for i in range(len(v) - 1):
if v[i][0] == v[i + 1][0]:
continue
else:
count += 1
if count == m:
for j in v:
r = j[0]
c = j[1]
ans[r][c] = 0
elif count < m / 2:
for j in v:
r1 = j[0]
c1 = j[1]
ans[r1][c1] = 1
else:
for t in v:
r2 = t[0]
c2 = t[1]
if r2 % 2 == 0:
ans[r2][c2] = 1
else:
ans[r2][c2] = 0

for i in range(len(ans)):
zeros = 0
ones = 0
for j in range(len(ans[0])):
if ans[i][j] == 0:
zeros += 1
else:
ones += 1
if zeros == ones:
for k in range(len(ans[0])):
if ans[i][k] == 0:
ans[i][k] = 1
else:
ans[i][k] = 0
elif zeros == 0 or ones == 0:
continue
else:
if ones % 2 == 1:
for j in range(len(ans[0])):
r = 0
if ones != 0:
ans[i][j] = 1
ones -= 1
r = 1
if ones > 0:
t1 = m - j - 1
ans[i][t1] = 1
ones -= 1
else:
if r == 1:
continue
if j <= t1:
ans[i][j] = 0
else:
break
m = int(input())
arr = []
dup = []
for _ in range(m):
dup = [t for t in input().split()]
arr.append(dup.copy())
ans = arr.copy()
dic = {}
matrix(arr, m, ans)
for i in range(len(ans)):
for j in range(len(ans[0]) - 1):
print(ans[i][j], end=" ")
print(ans[i][-1])


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