def isPalindrome(Str): Len = len(Str) if (Len = | CODING SOLUTION - Placement Jobs & Materials

def isPalindrome(Str):


Len = len(Str)



if (Len == 1):

return True




ptr1 = 0




ptr2 = Len - 1


while (ptr2 > ptr1):


if (Str[ptr1] != Str[ptr2]):

return False

ptr1 += 1

ptr2 -= 1


return True



def noOfAppends(s):


if (isPalindrome(s)):

return 0




del s[0]


return 1 + noOfAppends(s)

//CodingSolution

se = "abede"

s = [i for i in se]
print(noOfAppends(s))

Python
Make palindrome code
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