CODING SOLUTION - Placement Jobs & Materials

2022-02-19 15:17:08 GET TRAINED & SECURE YOUR PLACEMENT

According to Times of India, Only 3 percent Engineers get high quality tech jobs in India and the reason behind this is skills which are not competitive and enough to crack high tech interviews.

To fullfill this gap REGex has come with a program in which REGex will train and hire Candidates and even make you capable to crack companies interview. REGex will also helps students on functional projects to build their resumes and to make best future employers.

INDUSTRIAL INTERNSHIP / TRAINING PROGRAM - FEBRUARY 2022 by REGex Software Services ( Starting from 12th February 2022 Onwards ) with PLACEMENT OPPORTUNITY
To Get Extra 10% Off Use Code: Alpha10

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Python Django Full Stack Development: https://www.regexsoftware.com/python-django-feb-2022/ [ Starting from 19th Feb ]

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Java Full Stack Development: https://www.regexsoftware.com/java-full-stack-development-feb-2022/ [ Starting from 25th Feb ]

DataScience Progarm

DataScience Specialization Program: https://www.regexsoftware.com/datascience-specialization-program-feb-2022/ [ Starting from 25th Feb ]



JOIN & BOOK YOUR SEAT TODAY


PLACEMENT OPPORTUNIRY
REGex will train you & then provide Placement Assistance with average package of 6LPA based on your performance.



𝗕𝗘𝗡𝗘𝗙𝗜𝗧𝗦:
Live sessions + Access of recordings
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Training Completion Certificate and Project Completion / InternShip Certificate
[ GLOBALLY ACCEPTED ]


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To Get Extra 10% Off Use Code: Alpha10 Open / Comment

2022-02-19 15:17:08 Open / Comment

2022-02-19 14:53:35 Python
Linda code
Telegram - t.me/codingsolution_IT Open / Comment

2022-02-19 14:47:03 n = int(input())
l = list(map(int,input().split()))
l.sort()
if len(l) > 4:
B = l[:len(l)//2]
C = l[len(l)//2:]
print(B[-1]+B[-2]+C[-1]+C[-2])
else:
print(l[-1]+l[-2])


Python
Early bird Code
Telegram - t.me/codingsolution_IT Open / Comment

2022-02-19 14:38:58 Python
Early bird Code
Telegram - t.me/codingsolution_IT Open / Comment

2022-02-19 10:29:31 #include
int main(){
int a,b[20];
scanf("%d",&a);
scanf("%d",&b);
if(a==5){
printf("No");
else
printf("Yes");
return 0;
}

C programming
Research Lab
Telegram - t.me/codingsolution_IT

23.9K views07:29

Open / Comment

2022-02-19 10:09:35 Python
John code
Telegram - t.me/codingsolution_IT Open / Comment

2022-02-18 20:43:40 TCS NQT Solved Paper - 12th Sept 2021 [Morning Slot]:
Telegram - t.me/studymaterial_IT Open / Comment

2022-02-18 19:19:58 TCS NQT ALL SLOTS SOLUTION GROUP:

t.me/codingsolution_IT

t.me/tcs_nqt_exam_infosys_exam

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2022-02-17 11:32:41 INFOSYS & TCS IRC DRC SOLUTION GROUP:

t.me/codingsolution_IT

t.me/tcs_nqt_exam_infosys_exam

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