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The latest Messages 78
2022-02-03 14:14:31
Java
Fanny's Occurrences
Telegram - t.me/codingsolution_IT
10.4K views11:14
2022-02-01 19:12:26
Verbal Ability Placement Paper:
Telegram - t.me/studymaterial_IT
4.9K views16:12
2022-02-01 10:09:58
C++
def authentication (n):
A=list(range(1,n+1))
i=2
While i
A= A[j for j in range(len(A)) if j%i !=0]
i+=1
return ("Yes" if len(A)>0 else "No")
print(authentication(int(input()))
Python3
strong number
Telegram - t.me/codingsolution_IT
13.8K views07:09
2022-01-31 21:09:29
Infosys Off Campus Drive | 2019-2022 Batch | 2-3 LPA
Telegram - t.me/indiaoffcampusjobs
3.8K views18:09
2022-01-31 19:44:41
Accenture Aptitude Que & Ans:
Telegram - t.me/studymaterial_IT
5.9K views16:44
2022-01-30 18:36:38
MCQ Pseudocode Qsn:
Telegram - t.me/studymaterial_IT
6.1K views15:36
2022-01-29 18:45:11
Wipro Latest Placement Paper:
Telegram - t.me/studymaterial_IT
10.2K views15:45
2022-01-29 14:29:51
x=input()
s=0
if len(x)<=3:
for i in x:
s+=int(i)
else:
s+=int(s[-1])+int(s[-2])+int(s[-3])
print(s)
Python
Telegram - t.me/codingsolution_IT
18.0K views11:29
2022-01-29 14:25:40
n = int(input())
l = []
for i in range(n):
l.append(input())
dic = {}
for i in range(n):
x = len(l[i])
nam = l[i]
for j in range(x):
if nam[j] in dic.keys():
dic[nam[j]]+=1
else:
dic[nam[j]]=1
f = 1
for a in dic.keys():
if dic[a]%n!=0:
print('Not possible')
f = 0
break
if f:
print('Possible')
Python
A new application Code
Telegram - t.me/codingsolution_IT
15.8K views11:25
2022-01-29 14:20:56
C language
A new application Code
Telegram - t.me/codingsolution_IT
14.5K views11:20
C
