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CODING SOLUTION - Placement Jobs & Materials

Logo of telegram channel codingsolution_it — CODING SOLUTION - Placement Jobs & Materials C
Logo of telegram channel codingsolution_it — CODING SOLUTION - Placement Jobs & Materials
Channel address: @codingsolution_it
Categories: Technologies
Language: English
Subscribers: 200.30K
Description from channel

🌀 ” Our Only Aim Is To Let Get Placed To You In A Reputed Company. “
Contact Admin:
instagram.com/offcampusjobsindia_it

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The latest Messages 92

2022-01-06 16:36:58
C++
PRODUCT WITH THE SUCCESSOR Telegram - t.me/codingsolution_IT
10.8K views13:36
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2022-01-05 20:54:38 MINDTREE, HCL & ACCOLITE EXAM SOLUTION GROUP

Telegram - t.me/codingsolution_IT

Telegram - t.me/mindtree_exam_accolite_exam_hcl

Share post in ur college Whatsapp grps.
2.5K views17:54
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2022-01-04 15:47:49 DATASCIENCE SPECIALIZATION PLACEMENT PROGRAM
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8.8K views12:47
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2022-01-04 15:46:45
7.6K views12:46
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2022-01-03 20:39:09 LANDIS+GYR & TECH MAHINDRA EXAM SOLUTION GROUP

Telegram - t.me/codingsolution_IT

Telegram - t.me/Landis_gyr_tech_mahindra_exam

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3.0K views17:39
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2022-01-03 17:39:42 awk ' BEGIN{FS=#;count=0;}{

if($4>300){
count=count+$3;}

}END{
print "Total count:" count;}
else
{
print "No soap found with cost above 300";
}
}'

Soap management Unix code
Telegram - t.me/codingsolution_IT
6.3K views14:39
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2022-01-03 17:39:17 class Employee:
def _init_(self,n,d,s,lb):
self.name=n
self.designation=d
self.salary=s
self.leavesbalance=lb

class Organization:
def _init_(self,elist):
self.employee_list=elist

def display_leaves(self,name):
for i in self.employee_list:
if i.name==name:
for a,b in i.leavesbalance.items():
print(a,":",b)

def checkLeaveEligibility(self,ename,tl,nol):
for i in self.employee_list:
if i.name==ename:
for a,b in i.leavesbalance.items():
if a==tl:
if b>=nol:
i.leavesbalance[a]=b-nol
return 'True'
else:
return 'False'
return 'not found'
if _name_ == '_main_':
elist=[]
num=int(input())
for i in range(num):
leaves={}
name=input()
designation=input()
salary=int(input())
ltype=int(input())
for i in range(ltype):
key=input()
value=int(input())
leaves[key]=value
elist.append(Employee(name,designation,salary,leaves))
obj=Organization(elist)
empname=input()
Itype=input()
nol=int(input())
if(obj.checkLeaveEligibility(empname,Itype,nol)=='True'):
print("leave granted")
obj.display_leaves(empname)
elif(o.checkLeaveEligibility(empname,Itype,nol)=='False'):
print("leave not granted")
obj.display_leaves(empname)
elif(obj.checkLeaveEligibility(empname,Itype,nol)=='not found'):
print("leave not granted")
print("Employee not found")

Python
Employee code
Telegram - t.me/codingsolution_IT
6.5K views14:39
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2022-01-03 17:06:55 class Food:
def init(self,name,protien,fat,carb):
self.name=name
self.protien=protien
self.fat=fat
self.carb=carb

class Nutrition:
def init(self,status,lfood):
self.status=status
self.lfood=lfood
def setEnergy(self):
result=[]
for i in lfood:
for k,v in status.items():

temp=(i.protien+i.fat+i.carb)
if(temp>=v[0] and temp<=v[1]):
result.append(str(i.name)+" - "+str(temp)+" - "+k)
if(len(result)==0):
return None
else:
return result
def getEnergyRichFood(self,checkenergy):
ans=[]
for i in lfood:
temp=(i.protien+i.fat+i.carb)
if(temp<=checkenergy):
ans.append(i.name+" : "+str(temp))
if(len(ans)==0):
return None
else:
return ans
n=int(input())
lfood=[]

for i in range(n):
name=input()
protien=float(input())
fat=float(input())
carb=float(input())
lfood.append(Food(name,protien,fat,carb))
status={}
cnt=int(input())
for i in range(cnt):
st=input()
l=[]
l.append(int(input()))
l.append(int(input()))
status[st]=tuple(l)
checkenergy=int(input())
obj=Nutrition(status,lfood)
result=obj.setEnergy()
ans=obj.getEnergyRichFood(checkenergy)
if(result!=None):
print("Energy of Food:")
for i in result:
print(i)
if(ans!=None):
print("Food within given criteria:")
for i in ans:
print(i)
else:
print("No Food Found")

Python
Food code
Telegram - t.me/codingsolution_IT
8.0K views14:06
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2022-01-03 16:31:45 PYTHON TCS IRA:


1. 2003
2. All
3. Reinforcement
4. All the evidence
5.excellence
accurate, accessible
7. An update on the current status
8.person feel uncomfortable
12.D
50. C
7 d
8 b
9 c
10 d
11 c
12 13 D
2.4K views13:31
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2022-01-03 16:28:51 PYTHON TCS IRA:


1. 2003
2. All
3. Reinforcement
4. All the evidence
5.excellence
accurate, accessible
7. An update on the current status
8.person feel uncomfortable
12.D
50. C
7 d
8 b
9 c
10 d
11 c
12 13 D
2.7K viewsedited  13:28
Open / Comment