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EPYTHON LAB

Logo of telegram channel epythonlab — EPYTHON LAB E
Logo of telegram channel epythonlab — EPYTHON LAB
Channel address: @epythonlab
Categories: Technologies
Language: English
Subscribers: 5.40K
Description from channel

Welcome to EPYTHON LAB. The aim of EPYTHON LAB is to give data science and python training, and to develop and provide data science and analytical solutions for business problems.
Feel free to ask questions and support for members @pydiscussion

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The latest Messages 4

2022-06-16 12:06:50 How to Detect Outliers using Boxplot in Python



@epythonlab #subscribe_like_share
154 views09:06
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2022-06-14 18:32:11
What strategy do you use to fill missing values of your data?
Check out the above video for more info
Anonymous Poll
36%
Median
58%
Mean
7%
None
45 voters237 views15:32
Open / Comment
2022-06-14 12:52:05 How to deal with missing data?




@epythonlab #subscribe_share_and_like
343 viewsedited  09:52
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2022-06-13 08:32:53 The most essential skills every Python Developer should learn

There are a lot of String Manipulation Methods

You can Learn from the below tutorial

Please don't forget to subscribe, like and share to reach more people.

Thanks for your kind support



238 views05:32
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2022-06-11 18:38:48 Hey! Do you want to learn Data Cleansing with Pandas?
You can start learning here is the link of live stream




Don't forget to subscribe to our channel
We will continue teaching cleaning large volume of dataset
102 viewsedited  15:38
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2022-06-10 13:59:27 What is the fastest method to remove punctuation from a string?

How to Remove Punctuation from a String(3 different methods)




@epythonlab
299 viewsedited  10:59
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2022-06-10 08:28:57 Which method of counting the frequency of word occurrences in a sentence in Python? #python
https://lnkd.in/eqbmVkwZ
349 views05:28
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2022-06-09 09:48:59 Tokenizing Sentences in Python


229 views06:48
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2022-06-08 22:20:00 Implementing Bag of Words in Python


292 viewsedited  19:20
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2022-06-08 17:29:42
Poll 03

What will be the output of the following program? lst = ["epy", "thon", "lab"] for x in lst: x.upper() print(lst)
Anonymous Poll
76%
["EPY", "THON", "LAB"]
6%
[None, None, None]
18%
["epy", "thon", "lab"]
17 voters90 views14:29
Open / Comment