-> -> Fe and Fg are in same direction :- a=g+qE/m -> -> Fe and Fg are in opposite direction:- a=g-qE/m -> -> Fe and Fg are perpendicular to each other=a²=g²+[qE/m]² Force between two parallel wires having linear charge density λ1 and λ2 is F(on unit length)=2kλ1λ2/d If Fe=Fg for two Identical charges then q/m=√4π£oG 5.6K views17:42